In a quadrilateral ABCD, AO and BO are the bisectors of angle A and angle B. Prove that
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Given: AO and BO are bisectors of ∠A and ∠B
To Prove ![]()
Proof:
As AO and BO are bisectors,
and ![]()
We know that,
Sum of angles of a triangle = 180°
For Δ AOB,
∠AOB + ∠ABO + ∠AOB = 180°
![]()
∠A+ ∠B + 2 ∠AOB = 360°
∠A+ ∠B = 360° – 2 ∠AOB ……eq(1)
We also know that,
Sum of angles of a quadrilateral = 360°
For Quadrilateral ABCD,
∠A+ ∠B + ∠C + ∠D = 360°
Putting the value of ∠A+ ∠B from equation 1
360° – 2 ∠AOB + ∠C + ∠D = 360°
2 ∠AOB = ∠C + ∠D
![]()
Hence, Proved.
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