The sum of three consecutive natural numbers is 114. Find the numbers.
Let x, x + 1 and x + 2 be the three numbers.
Given: the sum of three numbers = 114
⇒ x + (x + 1) + (x + 2) = 114
⇒ 3x + 3 = 114
⇒ 3x = 111
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So, x + 1 = 38 and x + 2 = 39
∴ The three numbers are 37, 38 and 39.
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