Q9 of 21 Page 109

A net force of 20 N acts on a 5kg mass kept at rest. Distance travelled by the mass in 6 s is

Given:

Force = F = 20 N


Mass = m = 5 kg


We know


Force = mass x acceleration





Let the distance travelled by the particle in 6 s = s


A particle starts from rest so,


Initial velocity = u = 0





More from this chapter

All 21 →
7

A body constrained to move in the y-direction is subjected to a force N. The work done by this force in moving the body through a distance of 10 m along y-axis ithe s?

 8

If a bullet of mass 5 grams moving with velocity 100 ms–1 penetrates the wooden block up to 6 cm. Then the average force imposed by the bullet on the block is

 10

A force acts for 10s on a stationary body of mass 100kg after which the force ceases to act. The body moves through a distance of 100 m in the next 5s. Calculate

(a) The velocity acquired by the body


(b) The acceleration produced by the force


(c) The magnitude of the force.

 11

A train has to negotiate a curve of 400m by how much the outer rail be raised with respect to inner rail for speed 48 kmhr–1. The distance between rails is 1m?