A stone of mass 5kg falls from the top of a cliff 50m high and buries 1m in deep in sand. Find average resistance offered by sand.
Mass of stone = M = 5 kg
Height of the cliff = h = 50 m
Case I: before hitting the ground
Since the stone falls freely, a = g = 9.8 ms–2
Stone falls from rest, initial speed = u = 0
s = h = 50 m
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v = speed of stone before hitting the ground
Case II: After hitting the ground when stone penetrates the sand
Final speed = v = 0
Initial speed = u![]()
Distance travelled in sand = s = 1 m
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Negative sign indicates that it is retardation
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Negative sign indicates that its a resistive force
Average resistive force offered by the sand = ![]()
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