A Carnot engine whose sink is at 300K has an efficiency of 40%. By how much should the temperature of the source be increased to as to increase its efficiency by 50% of original efficiency?
A) 150 K
B) 250 K
C) 300 K
D) 450 K
Given,
Initially
The temperature of the sink =![]()
Let, the temperature of the source=![]()
The efficiency of a Carnot engine ![]()
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Now efficiency is increased by 50%
So, new efficiency =![]()
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Let, the new temperature of source = ![]()
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So the increase in temperature of source need to increase efficiency of Carnot engine by 50% = ![]()
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