Q22 of 37 Page 13

A chord of a circle of radius 10cm subtends a right angle at the centre. Use π=3.14 and find:

(i) area of the minor sector


(ii)area of the major sector


Given: Radius of the circle = OA = OB = 10 cm


and θ = 90°


(i) Area of the minor sector


"Area of minor sector "




= 3.14 × 25


= 78.5cm2



(ii) Area of major sector


Area of major sector = Area of circle - Area of minor sector = πr2 – 78.5


= 3.14 × (10)2 – 78.5


= 314 – 78.5


= 235.5 cm2


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