In an equilateral triangle of side 12cm, a circle is inscribed touching its sides. Find the area of the portion of the triangle not included in the circle. [Take √3=1.73 and π=3.14]

Area of shaded region = Area of ΔABC – Area of circle
Given side of triangle = 12cm
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= 36√3cm2
Now, we have to find the area of a circle. For that we need a radius.
Draw AD ⊥ BC
So, In BDO
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⇒ r = 2√3cm
Now, Area of circle = πr2
= 3.14 × (2√3)2
= 37.68cm2
Area of shaded region = Area of ΔABC – Area of circle
= 36√3 – 37.68
= 36(1.73) – 37.68
= 24.6cm2
Hence, the area of the portion of the triangle not included in the circle is 24.6cm2
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