Q12 of 27 Page 1

(i) By the standard electrode potential values stated for acid solutions, predict whether Ti4 + species may be used to oxidize Fe(II) to Fe(III)


(ii) Based on the data arrange Fe2 + , Mn2 + and Cr2 + in the increasing order of stability of +2 oxidation state. (Give a brief reason)


E°(Cr3 + /Cr2 + ) = - 0. 4V


E°(Mn3 + /Mn2 + ) = + 1. 5V


E°(Fe3 + /Fe2 + ) = + 0. 8V

(i) No Ti4 + cannot oxidize Fe(II) to Fe(III).


Reason:


As it is clearly stated that Ti4 + has lower reduction potential ( + 0. 01V) than Fe3 + ( + 0. 77V). Ti4 + cannot get reduced as compared to Fe3 + . Therefore Ti4 + cannot oxidise Fe(II) to Fe(III).


(ii) Cr3 + /Cr2 + < Fe3 + /Fe2 + < Mn3 + /Mn2 +


Reason:


As the value of reduction potential increases,the stability of the + 2 oxidation state also increases. Since, - 0. 4V<0. 8V<1. 5V


Cr3 + /Cr2 + < Fe3 + /Fe2 + < Mn3 + /Mn2 + .


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