Q15 of 27 Page 1

An alcohol A (C4H10O) on oxidation with acidified potassium dichromate gives acid B (C4H8O2). Compound A when dehydrated with conc. Sulphuric acid 443 K gives compound C. Treatment of C with aqueous H2SO4 gives compound D (C4H10O) which is an isomer of A. Compound D is resistant to oxidation but compound A can be easily oxidized. Identify A, B, C and D. Name the type of isomerism exhibited by A and d.

A =


B =


C =


D =


A and D exhibit position isomerism as they vary only in the position of the functional group(-OH)


Explanation:



(BUTANOL) (BUTANOIC ACID)


Butanol reacts with acidified potassium dichromate and gets oxidised to form butanoic acid. This reaction is also known as dehydrogenation reaction which leads to a loss of dihydrogen.



Butanoic acid gets reduced to form butene by the reaction of conc. sulphuric acid



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