A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. below), and these are equally likely outcomes. What is the probability that it will point at
(i) 8?
(ii) An odd number?
(iii) A number greater than 2?
(iv) A number less than 9?
Concept Used:
Explanation:
(i) Let E be an event of getting 8
Total Possible outcomes = 8
Total favourable outcomes = 1 (Since 8 occurs only one time)
Hence, the probability of getting 8 is 1/8.
(ii) Let E be an event of getting an odd number
Total Possible outcomes = 8
Total odd numbers = 1, 3, 5, 7
Total favourable outcomes = 4
Hence, the probability of getting an odd number is 1/2.
(iii) Let E be the event of getting a number greater than 2.
Total Possible outcomes = 8
Total numbers greater than 2 = 3, 4, 5, 6, 7, 8
Total favourable outcomes = 6
Hence, the probability of getting a number greater than 2 is 3/4.
(iv) Let E be the event of getting a number less than 9
Total Possible outcomes = 8
Total numbers less than 9 = 1, 2, 3, 4, 5, 6, 7, 8
Total favourable outcomes = 8
Hence, the probability of getting a number less than 9 is 1.
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