Three coins are tossed together. Find the probability of getting:
(i) exactly two heads
(ii) at most two heads
(iii) at least one head and one tail.
(iv) no tails
Concept Used:
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Explanation:
Sample space = {(H, H, H), (H, H, T), (H, T, T), (H, T, H), (T, H, H), (T, T, H), (T, H, T), (T, T, T)}
(i) P(Exactly two heads) =?
Now,
Total Possible outcomes = 8
Total favourable outcomes = 3
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(ii) P(at most two heads) =?
At most two heads mean that the number of heads should be 2 or less than 2.
Total Possible outcomes = 8
Total favourable outcomes = 4
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(iii) P(at least one head and at least one tail) =?
Total possible outcomes = 8
Total favourable outcomes = 6
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(iv) P(no tails) = ?
Total possible outcomes = 8
Total favourable outcomes = 1
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Couldn't generate an explanation.
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