Find the zeroes of the following polynomial:
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given polynomial is
5√5x2 + 30x + 8√5
Now factorizing by splitting the middle term.
Now we need to find two numbers whose sum is 30 and
Product is 5√5 × 8√5 = 5 × 8 × √5 × √5 = 40 × 5 = 200
So, the above given polynomial is
5√5x2 + 20x + 10x + 8√5
= 5√5x2 + 20x + (5 × 2) x + 8√5
= 5√5x2 + 20x + (√5 × √5 × 2) x + 8√5
= 5x (√5x + 4) + 2√5(√5x + 4)
= (5x + 2√5) (√5x + 4)
So, the zeroes of the polynomial will be
5x + 2√5 = 0 and √5x + 4 = 0
⇒ 5x = – 2√5 and √5x = – 4


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Hence the zeroes of the given polynomial are
and
.
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