Find the sum of the two middle most terms of an AP 
Given: AP ![]()
To find: ![]()
Formula Used: nth term of an AP is:
an = a + (n - 1) d
Explanation:
first term, a = ![]()
common difference, d![]()
last term, an = 4
= ![]()
using the nth term formula
an = a + (n - 1) d
![]()
13 = - 4 + (n - 1) [ multiplication by 3 on the both side]
13 + 4 = n - 1
n = 18
as n is even middle terms will be
i.e. 9th and 10th terms
a9 + a10 = a + 8d + a + 9d
= 2a + 17d
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