Q24 of 38 Page 5

Find the sum of the integers between 100 and 200 that are

not divisible by 9.

Given: integers between 100 and 200.


To find: Sum of integers between 100 and 200 not divisible by 9.


Formula Used:


Sum of “n” terms of an AP:



Where Sn is the sum of first n terms


nth term of an AP is:


an = a + (n - 1) d


Where an is the last term.


n = no of terms


a = first term


d = common difference


The sum of the integers between 100 and 200 which is not divisible by 9


= (sum of total numbers between 100 and 200) – ( sum of total numbers between 100 and 200 which is divisible by 9).


Let the required sum be S


S = S1 - S2


Where S1 is the sum of AP 101, 102, 103, - - - , 199


And S2 is the sum of AP 108, 117, 126, - - - - , 198


For S1


First term, a = 101


Common difference, d = 199


Let n be no of terms


Then,


an = a + (n - 1) d


199 = 101 + (n - 1 )1


98 = (n - 1)


n = 99


now, Sum of this AP


[ as last term is given]




= 99(150 )


= 14850


For S1


First term, a = 108


Common difference, d = 9


Last term, an = 198


Let n be no of terms


Then,


an = a + (n - 1) d


198 = 108 + (n - 1 )9


10 = (n - 1 )


n = 11


now, Sum of this AP





= 11(153)


= 1683


Therefore


S = S1 - S2


= 14850 - 1683


= 13167


More from this chapter

All 38 →