Q6 of 25 Page 9

In Fig. given below, find the area of ΔGEF.

Given that,

ABCD is rectangle


CD = 6 cm


AB = 6 cm (opp. sides of rectangle)


AD = 8 cm


We know that,


If a rectangle and a parallelogram are on the same base and between the same parallels, then the area of a triangle is equal to the half of parallelogram


Δ GEF and parallelogram ABCD are on the same base and between same parallels.


Area of parallelogram = Base × Height


Now,


Area Δ GEF = 1/2 × Area of ABCD


= 1/2 × AB × AD


= 1/2 × 6× 8


= 24 cm2


Hence,


Hence area Δ GEF is 24 cm2.


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Compute the area of trapezium PQRS in Fig. given below.

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In Fig. given below, ABCD is a trapezium in which AB||DC. Prove that ar(Δ AOD) = ar(Δ BOC).

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ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove that

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ABCD is a parallelogram. E is a point on BA such that BE = 2 EA and F is a point on DC, such that DF = 2FC. Prove that AECF is a parallelogram whose area is one third of the area of parallelogram ABCD.