Solve for x and y the following system of equations:

(CBSE 2008, 2009)
Given pair of linear equations is
…(i)
And
…(ii)
On multiplying Eq. (i) by 3 to make the coefficients equal of second term, we get the equation as
…(iii)
On adding Eq. (ii) and Eq. (iii), we get
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⇒ x – 1 = 3
⇒ x = 3 + 1
⇒ x = 4
On putting the value of x = 4 in Eq. (ii), we get
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⇒ (y – 2) = 3
⇒ y = 3 + 2
⇒ y = 5
Hence, x = 4 and y = 5 , which is the required solution.
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