Q17 of 17 Page 11

Draw a triangle ABC with BC = 6 cm, AB = 5 cm and ABC = 60°. Then construct a triangle whose sides are 3/4 of the corresponding sides of the ∆ ABC. . (CBSE 2018)

• STEPS OF CONSTRUCTION




1) Construct BC = 6cm





2) Construct an ABC of 60° at B. And, mark AB such that AB = 5cm. Join A and C to get the first ∆ ABC.









3) Draw a ray BX making an acute angle ABX at B.





4. Draw B1,B2,B3,B4 at equal lengths.



5. Join B4C and B3C parallel to B4C.



Thus ΔABC is the required triangle.


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