Two different dice are thrown together. Find the probability that the numbers obtained have
(i) even sum, and
(ii) even product.[CBSE 2017]
(i) When two dies are thrown together, the possible outcomes are=
{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}
Total no of possible outcomes = 36
Outcomes having even sum=
{(1, 1) (1, 3) (1, 5) (2, 2) (2, 4) (2, 6) (3, 1) (3, 3) (3, 5)
(4, 2) (4, 4) (4, 6) (5, 1) (5, 3) (5, 5) (6, 2) (6, 4) (6, 6)}
Total No of favorable outcomes = 18
And we know,
Probability of an event ![]()
P(Getting even sum) ![]()
(ii)
When two dies are thrown together, the possible outcomes are=
{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}
Total no of possible outcomes = 36
Outcomes having even product=
{(1, 2) (1, 4) (1, 6) (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6) (3, 2)
(3, 4) (3, 6) (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6) (5, 2) (5, 4)
(5, 6) (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)}
Total No of favorable outcomes = 27
And we know,
Probability of an event ![]()
P(Getting even product) ![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
[CBSE 2016]