Using properties of determinants, prove the following:

OR
Find the inverse of the following matrix using elementary operations :

Let’s Take L.H.S
L.H.S = 


Taking x, y and z common from R1 , R2 and R3 in the second determinant




Applying R2 - >R2 - R1 and R3 - >R2 - R1 , we get

Taking (y - x)(z - x) then , we get

Now, Expanding along Coloumn1
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Hence, Proved
OR
Given, A = 
To find: Find the inverse of the A
Explanation: We have given, A = 
We know, A = IA
Where I is the Identity Matrix

Applying R2 - >R2 + R1

Applying R2 - > R2 + 2R3

Applying R1→R1 - 2R2 and R3→R3 + 2R2

Applying R1→R1 + 2R3


Hence, This is the inverse of Matrix
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