Using properties of determinants, solve the following for x:

Given,

Applying C2→ C2 – 2C1 and C3→ C3 – 3C1
⇒ 
Applying R2→ R2 + R1 and R3→ R3 + 11R1
⇒ 
Expanding about the second column-
∴ (-1)![]()
⇒ (-18)(2x – 6) + 2(12x – 30) = 0
⇒ -36x + 24x +108 – 60 = 0
⇒ 12x = 48
∴ x = 48/12 = 4
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