Q26 of 45 Page 1

Sketch the graph of y =|x + 3| and evaluate the area under the curve
y =|x + 3| above x-axis and between
x = – 6 to x = 0

Given, y = |x + 3|


From basic idea of modulus function:


…(1)


As now we have the linear equations, and hence we can easily trace the straight lines


The curve bound the area as shown in figure-



Hence, Required area =


Using equation 1 we can write that –


Required area =


⇒ Required area =


⇒ Required area =


⇒ Required area =


⇒ Required area = = 9


∴ the area under the curve = 9 sq units


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