An experiment succeeds thrice as often as it fails. Find the probability that in the next five trials, there will be at least 3 successes.
Let p be probability of success and q be probability of failure of experiment
Given that p = 3q
As we have only two possibilities success or failure hence the distribution is binomial
And in binomial distribution p + q = 1
⇒ 3q + q = 1
⇒ q = 1/4
Put q = 1/4 in p + q = 1
⇒ p + 1/4 = 1
⇒ p = 1 – 1/4
⇒ p = 3/4
Now for binomial distribution the probability P(X=x) is given by
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Where n is the total number of trials and x is the required result
In 5 trials we require at least 3 success
Hence n = 5 and at least 3 means 3 success, 4 success or 5 success which means x = 3, 4 or 5
Hence required probability
⇒ required probability = P(X = 3) + P(X = 4) + P(X = 5)
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Using ![]()
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Hence the probability of at least 3 success in 5 trials is
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