Q21 of 45 Page 1

Find the particular solution of the differential equation x(1 + y2)dx - y(1 + x2)dy = 0, given that y = 1 when x = 0.

Given:






Now When x = 0 ⇒ y = 1


⇒ln(1 + 1) = ln (1 + 0) + ln C


⇒ ln 2 = ln C


⇒ C = 2





⇒2x2 – y2 + 1 = 0 (Particular Solution)


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