Q43 of 43 Page 5

If then find .  (CBSE 2017)





Using sin2θ + cos2θ = 1



Using 2sinθcosθ = sin2θ


y = sin–1(sin2θ)


Considering the limits,







For



Now, y = sin–1(sin2θ)


y = 2θ


y = 2cos–1x


Differentiating w.r.t x, we get



For



Now, y = sin–1(sin2θ)


y = –2θ


y = –2cos–1x


Differentiating w.r.t x, we get


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