Show that the four points A, B, C and D with position vectors
and
respectively are coplanar.
OR
The scalar product of the vector
with a unit vector along the sum of vectors
and
is equal to one. Find the value of λ and hence find the unit vector along
[CBSE 2014]
The position vectors of points
,
,
and ![]()
The points A, B, C and D are coplanar if the vectors
,
and
are coplanar
Vectors
,
and
are coplanar of ![]()
Let us first write the vectors
,
and ![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
![]()
Now let us find the value of ![]()
represents the determinant

Expand the determinant along the first row
![]()
![]()
![]()
![]()
Hence vectors
,
and
are coplanar and hence points A, B, C and D are coplanar
OR
,
and ![]()
Given that the dot product of
with unit vector along
is 1
![]()
![]()
To find a unit vector along
we have to divide by ![]()
Hence unit vector along ![]()



Take dot product of this unit vector along
with ![]()



![]()
Square both sides,
⇒ (2 + λ)2 + 40 = (6 + λ)2
⇒ 40 = (6 + λ)2 – (2 + λ)2
⇒ 40 = (6 + λ + 2 + λ)(6 + λ – 2 – λ)
⇒ 40 = (8 + 2λ)4
⇒ 10 = 2(4 + λ)
⇒ 5 = 4 + λ
⇒ λ = 1
Hence λ = 1.
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