Q3 of 71 Page 27

Write the coordinates of the foci of the hyperbola 9x2 – 16y2 = 144.

Given: 9x2 – 16y2 = 144


To find: coordinates of the foci f(m,n)


9x2 – 16y2 = 144





Formula used:


For hyperbola


Eccentricity(e) is given by,



Foci is given by (±ae, 0)


Here, a = 4 and b = 3





⇒ c = 5


Therefore,




Foci: (±5, 0)


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1

Write the eccentricity of the hyperbola 9x2 – 16y2 = 144.

 2

Write the eccentricity of the hyperbola whose latus-rectum is half of its transverse axis.

 4

Write the equation of the hyperbola of eccentricity, if it is known that the distance between its foci is 16.

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If the foci of the ellipse and the hyperbola coincide, write the value of b2