Q8 of 71 Page 27

The eccentricity of the hyperbola x2 – 4y2 = 1 is

Given: x2 – 4y2 = 1


To find: eccentricity(e)


x2 – 4y2 = 1




Formula used:


For hyperbola


Eccentricity(e) is given by,



Here, a = 1 and






Therefore,




Hence, eccentricity is

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