A manufacturer produces nuts and bolts. It takes 1 hour of work on machine A and 3 hours on machine B to produce a package of nuts. It takes 3 hours on machine A and 1 hour on machine B to produce a package of bolts. He earns a profit of Rs 17.50 per package on nuts and Rs 7 per package of bolts. How many packages of each should be produced each day so as to maximize his profits if he operates his machines for at the most 12 hours a day? Form the linear programming problem and solve it graphically.
Let x be the number of packages of nuts and y be the number of packages of bolts produced each day.
According to the given condition;

∴ x + 3y ≤ 12 and 3x + y ≤ 12 and x≤0, y≤0.
We need to maximize Z = 17.5x + 7y


∴ The maximum profit we can make is Rs. 73.5 by producing 3 packages of nuts and 3 packages of bolts.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

