Find :
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Let,
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⇒ x+3 = A(-4-2x)+B
⇒ x+3 = -2Ax-4A+B
Equating the coefficient, we get
-2A=1 and -4A+B =3
⇒ ![]()
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∴ ![]()
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Let ![]()
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Now , ![]()
Let 3-4x-x2= t
⇒ -4-2x dx= -(4+2x)dx =dt
∴ ![]()
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Again , ![]()
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Thus, ![]()

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