Solve the differential equation :
(tan-1y – x)dy = (1 + y2)dx.
OR
Find the particular solution of the differential equation
given that y = 1, when x = 0.
We have, (tan-1y – x)dy = (1 + y2)dx
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It is a linear differential equation of the form ![]()
Where,
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Now,
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Using:
, we get
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Putting ![]()
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OR
We have,
(i)
Which is a homogeneous differential equation.
Putting y=vx and
in (i), we get
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Integrating both sides, we get
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Substituting
, we get
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Given that, y=1 when x=0
From (ii), we get
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⇒ x2 = 2y2 log|y| is the solution of the given equation.
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