The random variable X can take only the values 0, 1, 2, 3. Given that
and
such that
find the value of p.
Given; Random variable X can take only the values 0, 1, 2,
3.
P(X=0) = P(X=1) = p and P(X=2) = P(X=3) = q and
⇒ P(X=0) + P(X=1) + P(X=2) + P(X=3) = 1
∴ 2p + 2q = 1 ……(i)
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∴ 0 + p + 4q + 9q = 2(0 + p + 2q + 3q)
∴ p − 3q = 0 ……(ii)
From (i) and (ii)
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