If the length of a wire is halved and its cross-sectional area is doubled, then what would be the resistance of the wire?
(Given, initially the resistance of the wire is R)
The formula of resistance is: ![]()
Where,
resistivity
Length of the conductor
A = Area of the conductor
If length of the conductor is halved then, ![]()
And, the cross sectional area is doubled, ![]()
![]()

![]()
Now, ![]()
![]()
Thus, we can conclude that the new resistance of the wire when the area of wire is doublead and length is haved become � the initial resistance.
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