Q6 of 32 Page 107

Solve for x, the inequalities in 4x + 3 ≥ 2x + 17, 3x – 5 < – 2.

Given,


4x + 3 ≥ 2x + 17


⇒ 4x – 2x ≥ 17 – 3


⇒ 2x ≥ 14


⇒ x ≥ 7 [1]


Also,


3x – 5 < - 2


⇒ 3x < 3


⇒ x < 1 [2]


As [1] and [2] are not possible together.


So, x has no solution.


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