Solve the following system of linear inequalities: 3x + 2y ≥ 24, 3x + y ≤ 15, x ≥ 4
Let’s plot the region of each inequality and then find the common region of all
3x + 2y ≥ 24
Line: 3x + 2y = 24
x | 0 | 8 |
y | 12 | 0 |
Also, (0, 0) doesn’t satisfy the 3x + 2y ≥ 24, hence region is away from the origin
3x + y ≤ 15
Line: 3x + y = 15
x | 0 | 5 |
y | 15 | 0 |
Also, (0, 0) satisfies the 3x + y ≤ 15, hence region is towards the origin
x ≥ 4 implies that region is right to the line x = 4, therefore graph is
It is clear from the graph the above system has no common region as solution

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