Q17 of 32 Page 107

Solve the following system of linear inequalities: 3x + 2y ≥ 24, 3x + y ≤ 15, x ≥ 4

Let’s plot the region of each inequality and then find the common region of all


3x + 2y ≥ 24


Line: 3x + 2y = 24














x



0



8



y



12



0



Also, (0, 0) doesn’t satisfy the 3x + 2y ≥ 24, hence region is away from the origin


3x + y ≤ 15


Line: 3x + y = 15














x



0



5



y



15



0



Also, (0, 0) satisfies the 3x + y ≤ 15, hence region is towards the origin


x ≥ 4 implies that region is right to the line x = 4, therefore graph is


It is clear from the graph the above system has no common region as solution




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