Using contrapositive method prove that if n2 is an even integer, then n is also an even integers.

Let us Assume

p: n² is an even integer.

~p: n is not an even integer

q: n is also an even integer

~q=n is not an even integer.

Since, In the contrapositive, a conditional statement is logically equivalent to its contrapositive.

Therefore,

~q → ~p = If n is not an even integer then n² is not an even integer.

Hence, ~q is true → ~p is true.