Solve sin 2x – sin 4x + sin 6x = 0
As we know,
So,
sin 2x + sin 6x – sin 4x = 0
⇒ 2 sin 4x cos 2x – sin 4x = 0
⇒ sin 4x (2 cos 2x – 1) = 0
∴ sin 4x = 0 or 2 cos 2x – 1 = 0
i.e. sin 4x = 0 or 
sin 4x = 0 or 
hence 4x = nπ or 
where n ∈ Z
So,
where n ∈ Z
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