Find the general solution of the equation sec2 2x = 1– tan 2x.
Given equation is
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⇒ ![]()
⇒ ![]()
⇒ tan 2x (tan 2x +1) = 0
⇒ tan 2x = 0 or (tan 2x +1) = 0
Now tan 2x = 0
⇒ tan 2x = tan 0
⇒ ![]()
⇒ ![]()
Now (tan 2x +1) = 0
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⇒
where n ∈Z
⇒
where n ∈Z and Z is set of integers
The general solution of the equation is
where n ∈Z and Z is set of integers
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