Write (i25)3 in polar form.
Given Complex number is Z = (i25)3
⇒ Z = i75
⇒ Z = i74.i
⇒ Z = (i2)37.i
We know that i2 = - 1
⇒ Z = ( - 1)37.i
⇒ Z = ( - 1).i
⇒ Z = - i
⇒ Z = 0 - i
We know that the polar form of a complex number Z = x + iy is given by Z = |Z|(cosθ + isinθ)
Where,
|Z| = modulus of complex number =![]()
θ = arg(z) = argument of complex number =![]()
Now for the given problem,
⇒ ![]()
⇒ ![]()
⇒ ![]()
⇒ |z| = 1
⇒ ![]()
Since x>0,y<0 complex number lies in 4th quadrant and the value of θ will be as follows - 900≤θ≤00.
⇒ ![]()
⇒
.
⇒ ![]()
⇒ ![]()
∴ The Polar form of Z = (i25)3 is
.
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