Write the complex number
in the polar form.
Let
,
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= - 1 + i
r = |z|
![]()
= √2
Let α be the acute angle given by,
![]()
![]()
= 1
⇒ α = π /4
As the point ( - 1,1) lies in the II quadrant.
∴ θ = arg(z) = π - α
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![]()
Hence polar form is:

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