Q12 of 26 Page 8

Find the 7th term in the expansion of

Given

Let it be T₇

We can write as T_{6 + 1} , then,

Now, we have

T_{6 + 1} = ¹⁰C₆ (3x²)^{10 - 6}.

T_{6 + 1} = ¹⁰C₆(3⁴) (x⁸)

T_{6 + 1} =

Thus, the 7^th Term of the given expression is .

Find the middle terms in the expansions of .

Using binomial theorem, prove that 2³ⁿ – 7n – 1 is divisible by 49, where n ∈ N.

Find the 7th term from the end in expansion of

Find the middle term of (1 + 3x + 3x² + x³)²ⁿ.

Questions · 26

8. Binomial Theorem

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