If the seventh term from the beginning and end in the binomial expansion of are equal, find n.

In the binomial expansion of

[(n + 1)-7 + 1]^th

i.e. (n - 5)^th term from the beginning is a 7^th term from the end.

Now, T₇ = T_{6 + 1}

T_{6 + 1} = ⁿC₆

= ⁿC₆

And, T_{n - 5 =} T_{n - 5 - 1}

T_{n - 6} = ⁿC_{n - 6} = ⁿC₆

It is given that,

T₇=T_{n - 5}

ⁿC₆ = ⁿC₆

On equating the exponent

n = 12

Hence, the value of n is 12