Find the middle term of (1 + 3x + 3x2 + x3)2n.
As (1 + 3x + 3x2 + x3)2n = ((1+x)3)2n
We can write as (1 + x)6n
Here, Total terms are 6n, i.e Even number
Then middle term = ![]()
Here, the middle term = ![]()
Now,
T3n + 1 = 6nC3n![]()
T3n + 1 = ![]()
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