Q8 of 28 Page 16

A pack of cards contains 4 aces, 4 kings, 4 queens and 4 jacks. Two cards are drawn at random. Find the probability that at least one of them is an ace.

As total number of cards = 16


2 cards can be drawn in 16C2 ways = 120 ways


As we need to find the probability for the event E such that at least one of them is an ace.


We can solve this problem using negation.


We will find the probability for event that both cards are ace (E’)


Automatically 1 – P(E’) will give P(E)


For finding P(E’) we will select both cards out of 4 ace cards.


∴ P(E’) =




Hence,



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