Q10 of 28 Page 16

Tickets numbered from 1 to 20 are mixed up together and then a ticket is drawn at random. What is the probability that the ticket has a number which is a multiple of 3 or 7?

We know,



the probability is to find the ticket drawn having a number which is a multiple of 3 or 7.


Since one ticket is drawn from a lot of mixed number, total possible outcomes are:


n(S)=20C1


=20


let E be the event of getting ticket which has number that is multiple of 3 or 7.


E= {3,6,9,12,15,18,7,14}


n(E)=8





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