Q2 of 43 Page 289

Find the median for the following frequency distribution:





















Class



4-8



8-12



12-16



16-20



20-24



24-28



Frequency



9



16



12



7



15



1



Here, we have grouped data given in the table. We need to find cumulative frequency of the data, which will predict our answer.

So,












































CLASS



FREQUENCY


(f)



CUMULATIVE FREQUENCY


(cf)



4 – 8



9



9



8 – 12



16



9 + 16 = 25



12 – 16



12



25 + 12 = 37



16 – 20



7



37 + 7 = 44



20 – 24



15



44 + 15 = 59



24 – 28



1



59 + 1 = 60



TOTAL



f = n = 60




We have added up all the values of the frequency in the second column and have got,


Total = n = 60


Now, we just need to find the value of n/2. So,




Now, look up for a value in the cumulative frequency just greater than 30.


We have, 37.


Corresponding to this value of cumulative frequency, we can say that median class is 12 – 16.


That is,


Median class = 12 – 16


we have almost everything we require to calculate median.


Median is given by,



Where,


l = lower limit of the median class = 12


n = Total number of observation (sum of frequencies) = 60


cf = cumulative frequency of the class preceding the median class = 25


f = frequency of the median class = 12


c = class size (class sizes are equal) = 4


Putting the values, l = 12, n/2 = 30, cf = 25, f = 12 and c = 4 in the given formula of median, we get





Median = 12 + 1.67


Median = 13.67


Thus, the median of the data is 13.67.


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