Find the median from following frequency distribution:
Class | 0-100 | 100-200 | 200-300 | 300-400 | 400-500 | 500-600 |
Frequency | 64 | 62 | 84 | 72 | 66 | 52 |
Here, we have grouped data given in the table. We need to find cumulative frequency of the data, which will predict our answer.
So,
CLASS | FREQUENCY (f) | CUMULATIVE FREQUENCY (cf) |
0 – 100 | 64 | 64 |
100 – 200 | 62 | 64 + 62 = 126 |
200 – 300 | 84 | 126 + 84 = 210 ← |
300 – 400 | 72 | 210 + 72 = 282 |
400 – 500 | 66 | 282 + 66 = 348 |
500 – 600 | 52 | 348 + 52 = 400 |
TOTAL | ∑f = n = 400 |
We have added up all the values of the frequency in the second column and have got,
Total = n = 400
Now, we just need to find the value of n/2. So,
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Now, look up for a value in the cumulative frequency just greater than 200.
We have, 210.
Corresponding to this value of cumulative frequency, we can say that median class is 200 – 300.
That is,
Median class = 200 – 300
∴ we have almost everything we require to calculate median.
Median is given by,

Where,
l = lower limit of the median class = 200
n = Total number of observation (sum of frequencies) = 400
cf = cumulative frequency of the class preceding the median class = 126
f = frequency of the median class = 84
c = class size (class sizes are equal) = 100
Putting the values, l = 200, n/2 = 200, cf = 126, f = 84 and c = 100 in the given formula of median, we get
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⇒ Median = 200 + 88.09
⇒ Median = 288.09
Thus, the median of the data is 288.09.
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