Solve < 1, when x ϵ R.

Observe that is zero at x = 5 and not defined at x = 2

Hence plotting these two points on number line

Now for x > 5, is negative

For every root and not defined value of the sign will change

We want the negative part hence x < 2 and x > 5

x < 2 means x is from negative infinity to 2 and x > 5 means x is from 5 to infinity

Hence x ∈ (-∞, 2) U (5, ∞)

Hence solution of is x ∈ (-∞, 2) U (5, ∞)