Solve the following systems of linear in equations:

–12 < 4 – ≤ 2

-12 < 4 – and 4 – ≤ 2

When,

-12 < 4 –

4 – > -12

Subtracting 4 from both the sides in above equation

4 – -4 > 12 – 4

– > -16

> -16

Multiplying both the sides by 5 in the above equation

> -16(5)

3x > -80

Dividing both the sides by 3 in above equation

>

Therefore,

x >

Now when,

4 – ≤ 2

Subtracting both the sides by 4 in the above equation

4 – – 4 ≤ 2 – 4

– ≤ - 2

≤ -2

Multiplying both the sides by 5 in the above equation

3x ≤ -10

Dividing both the sides by 3 in the above equation

≤

Therefore,

Therefore: