Solve the following systems of linear in equations:

5x – 7 < (x + 3), 1 –x – 4

When,

5x – 7 < x + 3

Adding 7 to both the sides in the above equation

5x – 7 + 7 < x + 3 + 7

5x < x + 10

Now, subtracting x from both the sides

5x – x < x + 10 -x

4x < 10

Dividing both the sides by 4 in above equation

Now when,

1 – ≥ x – 4

Subtracting 1 from both the sides in the above equation

1 - -1 ≥ x – 4 – 1

≥ x - 5

Now multiplying both the sides by 2 in the above equation

≥ 2x – 10

-3x ≥ 2x – 10

Now subtracting 2x from both the sides in the above equation

-3x – 2x ≥ 2x -10 – 2x

-5x ≥ -10

Now, multiplying both the sides by -1 in the above equation

-5x(-1) ≥ -10(-1)

5x ≤ 10

Now, dividing both the sides by 5 in the above equation

x ≤ 2

Therefore,

and x ≤ 2