To Find: Principal solution.
[NOTE: The solutions of a trigonometry equation for which 0
x
2
is called principal solution]
(i) Given: 
Formula used: sin
= sin
= n
+ (-1)n
, n
I
By using above formula, we have
= sin
x = n
+
(-1)n
Put n= 0
x = 0
+
(-1)0
x = ![]()
Put n= 1
x = 1
+
(-1)1
x =
1
x =
= ![]()
So principal solution is x=
and ![]()
(ii) Given: 
Formula used: cos
= cos
= 2n
, n
I
By using above formula, we have
= cos
= 2n
, n
I
Put n= 0
x = 2n
x = ![]()
Put n= 1
x = 2
x =
,
x =
,![]()
[
2
So it is not include in principal solution]
So principal solution is x=
and ![]()
(iii) Given: ![]()
Formula used: tan
= tan
= n
, n
I
By using above formula, we have
= tan
x = n
, n
I
Put n= 0
x = n
x = ![]()
Put n= 1
x =
x =
x = ![]()
So principal solution is x=
and ![]()
(iv) Given: ![]()
We know that tan
cot
= 1
So cotx =
tanx = ![]()
The formula used: tan
= tan
= n
, n
I
By using the above formula, we have
tanx =
= tan
= n
, n
I
Put n= 0
x = n
x = ![]()
Put n= 1
x =
x = ![]()
So principal solution is x=
and ![]()
(v) Given: cosec x = 2
We know that cosec
sin
= 1
So sinx = ![]()
Formula used: sin
= sin
= n
+ (-1)n
, n![]()
By using above formula, we have
sinx =
= sin
= n
+
(-1)n
Put n= 0
= 0
+
(-1)0
= ![]()
Put n= 1
= 1
+
(-1)1
=
1
=
= ![]()
So principal solution is x=
and ![]()
(vi) Given: sec x = ![]()
We know that sec
cos
= 1
So cosx = ![]()
Formula used: cos
= cos
= 2n
, n
I
By using the above formula, we have
cosx =
= cos
x = 2n
, n
I
Put n= 0
x = 2n
x = ![]()
Put n= 1
x = 2
x =
,
x =
,![]()
[
2
So it is not include in principal solution]
So principal solution is x=
and ![]()
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